author: unknown
Doing as the title suggests, we find the rain falls as so:
Reading off the wet numbers gives the 56-bit string:
01110100 01111100 11110001 00011000 01110011 10111000 01000101
Unfortunately this is nonsense in ASCII. Redoubling our efforts, we transcribe the full background bit string as follows (with spaces for barriers):
01010100 01 0 10 1 0000 1 11 0010100100000010011 00 01101111 1 01 1 10 1 0 1 0 0 0110010000100000011 10 011 01100001 0 11 1 0 00 1 0010110010000100000 0 111010001101111 0 0010 0000010011100110111 10110000101101 0000010 1100001000000110011 10 11011110010 0 00 0 01 1 1 0100101101110011101 00 11 0 1 1 1 0 1 00111 1 1 11 001000000111010001101 00 100010001100 00 1 10 010 0 1 0 0 1 0 0 1 0 1 1 0 0 00001 000001011100100 111011100001000101 1101011
Then, removing the flooded bits from the above, we obtain:
01010100 01 10 1 0000 11 0010100100000010011 00 01101111 01 1 10 0 1 0 0110010000100000011 10 011 01100001 0 11 0 1 0010110010000100000 0 111010001101111 0010 0000010011100110111 10110000101101 0000010 1100001000000110011 10 11011110010 0 00 0 01 1 0100101101110011101 00 0 1 1 0 1 1 11 001000000111010001101 00 00 1 10 010 1 0 0 1 0 0 00001 000001011100100 1101011
Which is a reasonable ASCII message: The Lord said to Noah, go into the Ark
.